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X^2-28X+122=0
a = 1; b = -28; c = +122;
Δ = b2-4ac
Δ = -282-4·1·122
Δ = 296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{296}=\sqrt{4*74}=\sqrt{4}*\sqrt{74}=2\sqrt{74}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2\sqrt{74}}{2*1}=\frac{28-2\sqrt{74}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2\sqrt{74}}{2*1}=\frac{28+2\sqrt{74}}{2} $
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